Sin34°⋅cos19°−cos34°⋅sin19°

Предыдущий
вопрос Следующий
вопрос

To find the value of sin(34°)⋅cos(19°)−cos(34°)⋅sin(19°), we can use the trigonometric identity for the sine of the difference of two angles:

sin(a - b) = sin(a)⋅cos(b) - cos(a)⋅sin(b)

Therefore, sin(34°)⋅cos(19°)−cos(34°)⋅sin(19°) becomes sin(34° - 19°) = sin(15°).

Therefore, sin(34°)⋅cos(19°)−cos(34°)⋅sin(19°) = sin(15°) ≈ 0.258819