3х1+х2-2х3=65х1-3х2+2х3=-44х1-2х2-3х3=-2

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To solve this system of linear equations, we can use the method of substitution or elimination. Here, let's use the substitution method.

From the first equation:
3x1 + x2 - 2x3 = 65

Rearranging, we get:
x2 = 65 - 3x1 + 2x3

Substitute x2 into the second equation:
x1 - 3(65 - 3x1 + 2x3) + 2x3 = -44
x1 - 195 + 9x1 - 6x3 + 2x3 = -44
10x1 - 4x3 = 151
5x1 - 2x3 = 75

Now, substitute x2 into the third equation:
x1 - 2(65 - 3x1 + 2x3) - 3x3 = -2
x1 - 130 + 6x1 - 4x3 - 3x3 = -2
7x1 - 7x3 = 128
x1 - x3 = 18.2857

Now we have two equations:
5x1 - 2x3 = 75
x1 - x3 = 18.2857

Solving these two equations simultaneously will give you the values of x1 and x3. After finding x1 and x3, you can substitute them back into any of the original equations to find the value of x2.