X^2+3x+4=04x^2-20x+26=0

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вопрос

To solve the quadratic equation:

x^2 + 3x + 4 = 0

We can use the quadratic formula:

x = [-b ± √(b^2 - 4ac)] / 2a

In this case, a = 1, b = 3, and c = 4. Plugging these values into the quadratic formula:

x = [-3 ± √(3^2 - 414)] / 2*1

x = [-3 ± √(9 - 16)] / 2

x = [-3 ± √(-7)] / 2

Since the square root of a negative number is not a real number, the solutions to this quadratic equation are complex numbers.