Cos(π/2-x) - sin(-x) + 2sin(π+x) = sin(x) - sin(-x) + 2sin(π+x)

Using trigonometric identities:
sin(-x) = -sin(x)
sin(π+x) = sin(π)cos(x) + cos(π)sin(x) = 0*cos(x) + (-1)sin(x) = -sin(x)

Therefore:
sin(x) - sin(-x) + 2sin(π+x) = sin(x) - (-sin(x)) + 2(-sin(x)) = sin(x) + sin(x) - 2sin(x) = 2sin(x) - 2sin(x) = 0

So, Cos(π/2-x) - sin(-x) + 2sin(π+x) equals 0.