а)1,7×(a-11)-16,3 =1,7×(3,8-11)-16,3 =1,7×(-7,2)-16,3 =-12,24-16,3 =-28,54
Ответ: -28,54
б)0,6(4x-14)-0,4(5x-1) =0,6(4(4\frac{1}{6})-14)-0,4(5(4\frac{1}{6})-1) =0,6(\frac{25}{6}-14)-0,4(\frac{26}{6}-1) =0,6(\frac{25}{6}-\frac{84}{6})-0,4(\frac{26}{6}-1) =0,6(-\frac{59}{6})-0,4(-\frac{13}{6}) =-\frac{177}{10}+\frac{13}{15} =-\frac{177}{10}+\frac{26}{30} =-\frac{177}{10}+\frac{78}{30} =-\frac{177}{10}+\frac{26}{10} =-\frac{151}{10} = -15,1
Ответ: -15,1
а)
1,7×(a-11)-16,3 =
1,7×(3,8-11)-16,3 =
1,7×(-7,2)-16,3 =
-12,24-16,3 =
-28,54
Ответ: -28,54
б)
0,6(4x-14)-0,4(5x-1) =
0,6(4(4\frac{1}{6})-14)-0,4(5(4\frac{1}{6})-1) =
0,6(\frac{25}{6}-14)-0,4(\frac{26}{6}-1) =
0,6(\frac{25}{6}-\frac{84}{6})-0,4(\frac{26}{6}-1) =
0,6(-\frac{59}{6})-0,4(-\frac{13}{6}) =
-\frac{177}{10}+\frac{13}{15} =
-\frac{177}{10}+\frac{26}{30} =
-\frac{177}{10}+\frac{78}{30} =
-\frac{177}{10}+\frac{26}{10} =
-\frac{151}{10} = -15,1
Ответ: -15,1