У^2-7/у^2-6y-9y-24/6у-у^2-3y-19/y^2-6y Плиииз

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вопрос

У^2-7/у^2-6y-9y-24/6у-у^2-3y-19/y^2-6y

First, let's simplify the expression step by step:

Factor the denominator of the first fraction: у^2-6y = y(y-6)

Factor the denominator of the second fraction: у^2-3y-19 = (у-7)(у+2)

Factor the denominator of the third fraction: у^2-6y = y(y-6)

Now our expression looks like this:

(y^2-7)/(y(y-6)) - (9y+24)/(6y+у^2+3y+19) / (y^2-6y)

Next, let's simplify the expression further:

Simplify the first fraction by factoring out a y-6 in the numerator: y^2-7 = (у+1)(у-7)

Simplify the second fraction by factoring out a common factor in the numerator and denominator: 9y+24 = 3(3y+8)

Now our expression is:

((у+1)(у-7))/(y(y-6)) - 3(3y+8)/(6y+y^2+3y+19) / (y^2-6y)

Lastly, let's combine the fractions:

((у+1)(у-7)-(3(3y+8)))/(y(y-6)(6+y+3+y^2) / (y^2-6y)

At this point, the expression is simplified as much as possible without actually performing the final calculations. I hope this helps! Let me know if you need any further clarification.