A) (1-i) + (7-3i) = 1 + 7 - i - 3i = 8 - 4i
B) (5-4i) -(7+4i) = 5 - 4i - 7 - 4i = -2 - 8i
C) (3+2i) (2-1i) = 32 + 3(-1i) + 2i2 + 2i*(-1i) = 6 - 3i + 4i - 2 = 4 + i
D) \frac{3-2i}{1+3i} = \frac{(3-2i)(1-3i)}{(1+3i)(1-3i)} = \frac{3-9i-2i+6i^2}{1-9i+3i-9i^2} = \frac{3-11i-6}{1+9} = -3 - i
E) (-i)^29 = (-1)^29 * i^29 = -i
A) (1-i) + (7-3i) = 1 + 7 - i - 3i = 8 - 4i
B) (5-4i) -(7+4i) = 5 - 4i - 7 - 4i = -2 - 8i
C) (3+2i) (2-1i) = 32 + 3(-1i) + 2i2 + 2i*(-1i) = 6 - 3i + 4i - 2 = 4 + i
D) \frac{3-2i}{1+3i} = \frac{(3-2i)(1-3i)}{(1+3i)(1-3i)} = \frac{3-9i-2i+6i^2}{1-9i+3i-9i^2} = \frac{3-11i-6}{1+9} = -3 - i
E) (-i)^29 = (-1)^29 * i^29 = -i