To find the value of t that satisfies the equation sin(π/2 + t) - cos(π + t) + 1 = 0, we can rewrite the sine and cosine functions in terms of the angle t.
sin(π/2 + t) = cos(t) and cos(π + t) = -cos(t)
Substitute these values into the equation to get:
cos(t) - (-cos(t)) + 1 = 02cos(t) + 1 = 02cos(t) = -1cos(t) = -1/2
Since the cosine function is negative in the second and third quadrants, we can find the reference angle by taking the inverse cosine of -1/2:
t = arccos(-1/2)t = 2π/3 or t = 4π/3
Therefore, the values of t that satisfy the equation sin(π/2 + t) - cos(π + t) + 1 = 0 are t = 2π/3 and t = 4π/3.
To find the value of t that satisfies the equation sin(π/2 + t) - cos(π + t) + 1 = 0, we can rewrite the sine and cosine functions in terms of the angle t.
sin(π/2 + t) = cos(t) and cos(π + t) = -cos(t)
Substitute these values into the equation to get:
cos(t) - (-cos(t)) + 1 = 0
2cos(t) + 1 = 0
2cos(t) = -1
cos(t) = -1/2
Since the cosine function is negative in the second and third quadrants, we can find the reference angle by taking the inverse cosine of -1/2:
t = arccos(-1/2)
t = 2π/3 or t = 4π/3
Therefore, the values of t that satisfy the equation sin(π/2 + t) - cos(π + t) + 1 = 0 are t = 2π/3 and t = 4π/3.