Sin45°+cos45°+2sin30°-4cos60°

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вопрос

Let's first find the values of sin45°, cos45°, sin30°, and cos60°:

sin45° = √2/2
cos45° = √2/2
sin30° = 1/2
cos60° = 1/2

Now we can substitute these values into the expression:

sin45° + cos45° + 2sin30° - 4cos60°
= √2/2 + √2/2 + 2(1/2) - 4(1/2)
= √2/2 + √2/2 + 1 - 2
= √2/2 + √2/2 - 1

Therefore, sin45° + cos45° + 2sin30° - 4cos60° simplifies to √2/2 + √2/2 - 1