Завершите решение.
[tex]\left \{ {{4x+5y=23} \atop {x+2y=8}} \right. =\ \textgreater \ \left \{ {{y=}\frac{23-4x}{5} \atop {x+2y=8}} \right.[/tex]

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вопрос

[tex]\left { {{4x+5y=23} \atop {x+2y=8}} \right. =\ \textgreater \ \left { {{y=\frac{23-4x}{5}} \atop {x+2(\frac{23-4x}{5})=8}} \right.[/tex]

[tex]\left { {{4x+5y=23} \atop {x+2y=8}} \right. =\ \textgreater \ \left { {{y=\frac{23-4x}{5}} \atop {x+2(\frac{23-4x}{5})=8}} \right.[/tex]

[tex]\left { {{4x+5y=23} \atop {x+2y=8}} \right. =\ \textgreater \ \left { {{y=\frac{23-4x}{5}} \atop {x+\frac{46-8x}{5}=8}} \right.[/tex]

[tex]\left { {{4x+5y=23} \atop {x+2y=8}} \right. =\ \textgreater \ \left { {{y=\frac{23-4x}{5}} \atop {\frac{5x+46-8x}{5}=8}} \right.[/tex]

[tex]\left { {{4x+5y=23} \atop {x+2y=8}} \right. =\ \textgreater \ \left { {{y=\frac{23-4x}{5}} \atop {\frac{-3x}{5}=-6}} \right.[/tex]

[tex]\left { {{4x+5y=23} \atop {x+2y=8}} \right. =\ \textgreater \ \left { {{y=\frac{23-4x}{5}} \atop x=10} \right.[/tex]

Решение:
[tex]x=10[/tex]
[tex]y=\frac{23-4(10)}{5} = 1[/tex]