Log10 100 + 2log5 125 - 3log1 2
First, let's simplify each logarithm:Log10 100 = 2 (since 10^2 = 100)2log5 125 = 2(log5 5^3) = 2(3) = 6 (since 5^3 = 125)3log1 2 = 3(0) = 0 (since any number raised to the power of 0 is 1)
Now, let's substitute these simplified values back into the original expression:2 + 6 - 0 = 8
Therefore, Log10 100 + 2log5 125 - 3log1 2 = 8.
Log10 100 + 2log5 125 - 3log1 2
First, let's simplify each logarithm:
Log10 100 = 2 (since 10^2 = 100)
2log5 125 = 2(log5 5^3) = 2(3) = 6 (since 5^3 = 125)
3log1 2 = 3(0) = 0 (since any number raised to the power of 0 is 1)
Now, let's substitute these simplified values back into the original expression:
2 + 6 - 0 = 8
Therefore, Log10 100 + 2log5 125 - 3log1 2 = 8.