tg(π/2 - α) = cot(α) = 1/tg(α) = 1/tg(π/2 - α) = 1/cot(α) = ctg(α).
Следовательно, tg(π/2 - α) + ctg(α - π/2) = tg(α) + ctg(α) = 1.
Ответ: 1.
tg(π/2 - α) = cot(α) = 1/tg(α) = 1/tg(π/2 - α) = 1/cot(α) = ctg(α).
Следовательно, tg(π/2 - α) + ctg(α - π/2) = tg(α) + ctg(α) = 1.
Ответ: 1.