Y''+y'-6y=0 если y=3 y'=1 при x=o

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вопрос

To find the value of the constant c we can plug in y=3 and y'=1 when x=0 into the given differential equation.

y'' + y' - 6y = 0

Substitute y=3, y'=1, x=0 into the equation:

3 + 1 - 6(3) = 0
4 - 18 = 0
-14 = 0

This equation does not hold, there may be an error in either the question or the calculations.