2\3А*7\12B
8\9х * 1 целую 4\5
5м *2целых6\11 * 2целых 5\14

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вопрос

To solve this expression, we need to carry out the operations in the order they appear:

Start with 2/3A 7/12B
2/3A = 2/3 times A
7/12B = 7/12 times B
Multiply these two fractions: (2/3) (7/12) = 14/36 = 7/18AB

Next, 8/9x 1 (whole number) 4/5
8/9x = 8/9 times x
1 (whole number) = 1
4/5 = 4/5
Multiply these fractions and the whole number: (8/9) 1 * (4/5) = 32/45x

Lastly, 5m 2 (whole number) 6/11 2 (whole number) 5/14
5m = 5 times m
2 (whole number) = 2
6/11 = 6/11
2 (whole number) = 2
5/14 = 5/14
Multiply these terms: (5) (2) (6/11) (2) (5/14) = 1200/77m