To subtract mixed numbers, we need to first convert them to improper fractions.
[ 5\frac{7}{8} = \frac{8 \times 5 + 7}{8} = \frac{40 + 7}{8} = \frac{47}{8} ]
[ 3\frac{5}{6} = \frac{6 \times 3 + 5}{6} = \frac{18 + 5}{6} = \frac{23}{6} ]
Now we can subtract the fractions:
[ 5\frac{7}{8} - 3 \frac{5}{6} = \frac{47}{8} - \frac{23}{6} ]
To subtract these fractions, we need to find a common denominator. The least common multiple of 8 and 6 is 24.
[ \frac{47}{8} = \frac{47 \times 3}{8 \times 3} = \frac{141}{24} ]
[ \frac{23}{6} = \frac{23 \times 4}{6 \times 4} = \frac{92}{24} ]
Now we can subtract:
[ \frac{141}{24} - \frac{92}{24} = \frac{141 - 92}{24} = \frac{49}{24} ]
Finally, we can convert the improper fraction back to a mixed number:
[ \frac{49}{24} = 2\frac{1}{24} ]
Therefore,
[ 5\frac{7}{8} - 3 \frac{5}{6} = 2\frac{1}{24} ]
To subtract mixed numbers, we need to first convert them to improper fractions.
[ 5\frac{7}{8} = \frac{8 \times 5 + 7}{8} = \frac{40 + 7}{8} = \frac{47}{8} ]
[ 3\frac{5}{6} = \frac{6 \times 3 + 5}{6} = \frac{18 + 5}{6} = \frac{23}{6} ]
Now we can subtract the fractions:
[ 5\frac{7}{8} - 3 \frac{5}{6} = \frac{47}{8} - \frac{23}{6} ]
To subtract these fractions, we need to find a common denominator. The least common multiple of 8 and 6 is 24.
[ \frac{47}{8} = \frac{47 \times 3}{8 \times 3} = \frac{141}{24} ]
[ \frac{23}{6} = \frac{23 \times 4}{6 \times 4} = \frac{92}{24} ]
Now we can subtract:
[ \frac{141}{24} - \frac{92}{24} = \frac{141 - 92}{24} = \frac{49}{24} ]
Finally, we can convert the improper fraction back to a mixed number:
[ \frac{49}{24} = 2\frac{1}{24} ]
Therefore,
[ 5\frac{7}{8} - 3 \frac{5}{6} = 2\frac{1}{24} ]