To solve the system of equations:
1) 5u + 2v = -192) u - 5v = -47
Let's solve equation 2 for u:u = -47 + 5v
Now, substitute the value of u in equation 1:5(-47 + 5v) + 2v = -19-235 + 25v + 2v = -1927v = -19 + 23527v = 216v = 216 / 27v = 8
Now, substitute the value of v back into the equation to solve for u:u = -47 + 5(8)u = -47 + 40u = -7
Therefore, the solution to the system of equations is:u = -7v = 8
To solve the system of equations:
1) 5u + 2v = -19
2) u - 5v = -47
Let's solve equation 2 for u:
u = -47 + 5v
Now, substitute the value of u in equation 1:
5(-47 + 5v) + 2v = -19
-235 + 25v + 2v = -19
27v = -19 + 235
27v = 216
v = 216 / 27
v = 8
Now, substitute the value of v back into the equation to solve for u:
u = -47 + 5(8)
u = -47 + 40
u = -7
Therefore, the solution to the system of equations is:
u = -7
v = 8