arccos(-1) = π arctg(1/√3) = π/6 arcsin(√2/2) = π/4
Теперь подставим значения: π + π/6 - π/4 = 4π/4 + 2π/12 - 3π/12 = 12π/12 + 2π/12 - 3π/12 = 11π/12
Итак, arccos (-1) + arctg 1/√3 - arcsin √2/2 = 11π/12.
arccos(-1) = π
arctg(1/√3) = π/6
arcsin(√2/2) = π/4
Теперь подставим значения:
π + π/6 - π/4
= 4π/4 + 2π/12 - 3π/12
= 12π/12 + 2π/12 - 3π/12
= 11π/12
Итак, arccos (-1) + arctg 1/√3 - arcsin √2/2 = 11π/12.