|5-3x|> 1
|x×2|>_ 0
|3x-7|>_ -8

Предыдущий
вопрос Следующий
вопрос

To solve the inequality |5-3x| > 1, we must consider two cases:

Case 1: 5-3x > 1
5 > 3x
x < 5/3

Case 2: -(5-3x) > 1
3x - 5 > 1
3x > 6
x > 2

Therefore, the solution to the inequality |5-3x| > 1 is x < 5/3 or x > 2.

To solve the inequality |x×2| ≥ 0, we note that the absolute value of any real number is always greater than or equal to 0. Therefore, the solution to |x×2| ≥ 0 is all real numbers x.

To solve the inequality |3x-7| ≥ -8, we note that the absolute value of any real number is always greater than or equal to 0. Therefore, the solution to |3x-7| ≥ -8 is all real numbers x.