Y'=cos^2(2x)

Предыдущий
вопрос Следующий
вопрос

To find the derivative of Y with respect to x, we can use the chain rule.

Let u = 2x, then Y' = (cos(u))^2.

Now, differentiate with respect to u:

(d/du) cos(u) = -sin(u).

Now, multiply by the derivative of the inside function:

Y' = -2sin(2x)cos(2x)

Therefore, Y' = -2sin(2x)cos(2x).