Log(3x-6)-Log2*3=Log2*3

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To solve this equation, we need to combine the logs on the left side using the properties of logarithms.

First, we can use the property that states Log(a) - Log(b) = Log(a/b) to combine the two logs:

Log((3x-6)/(23)) = Log23

Next, simplify the expression inside the log on the left side:

Log((3x-6)/6) = Log2*3

Now, we can eliminate the logs by setting the expressions inside the logs equal to each other:

(3x-6)/6 = 2*3

Simplify the right side:

(3x-6)/6 = 6

Now, we can solve for x by multiplying both sides by 6:

3x-6 = 36

Add 6 to both sides:

3x = 42

Divide by 3:

x = 14

Therefore, the solution to the equation is x = 14.