[tex] {183}^{0} \times {5}^{3} \div {3}^{2} + \frac{2}{9} [/tex]

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вопрос

To solve this expression, we will follow the order of operations (parentheses, exponents, multiplication and division from left to right, and addition and subtraction from left to right).

First, we calculate the exponents:
[ {183}^{0} = 1 ]
[ {5}^{3} = 5 \times 5 \times 5 = 125 ]
[ {3}^{2} = 3 \times 3 = 9 ]

Next, we perform the multiplication and division:
[ 1 \times 125 \div 9 = 125 \div 9 = 13\frac{8}{9} ]

Finally, we add the fraction:
[ 13\frac{8}{9} + \frac{2}{9} = 13\frac{10}{9} = 14\frac{1}{9} ]

Therefore, the final answer to the expression is (14\frac{1}{9}).