Y=-1(x+3)^2+4
y=(x-5)^2+4
y=-(x-2)^2+4
y=-(x-1)^2-1

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вопрос

These equations are all in vertex form, and each represents a parabolic function. The vertex form of a quadratic function is given as:

y = a(x - h)^2 + k

where (h,k) represents the vertex of the parabola and 'a' defines whether the parabola will open upwards or downwards.

y = -1(x+3)^2 + 4
Vertex: (-3, 4), opens downwards

y = (x-5)^2 + 4
Vertex: (5, 4), opens upwards

y = -(x-2)^2 + 4
Vertex: (2, 4), opens downwards

y = -(x-1)^2 - 1
Vertex: (1, -1), opens downwards