To solve the equation log4(3x+4) = 0, we first need to rewrite it in exponential form.
The logarithmic equation log4(3x+4) = 0 can be rewritten as 4^0 = 3x+4.
Since any number raised to the power of 0 is 1, we have 1 = 3x + 4.
Subtracting 4 from both sides gives us:1 - 4 = 3x-3 = 3x
Dividing by 3 on both sides:x = -1
Therefore, the solution to the equation log4(3x+4) = 0 is x = -1.
Now, let's simplify the expression 5 log2(x+10).
Using the logarithmic property log_a(x^b) = blog_a(x), we can rewrite the expression as:5 log2(x+10) = log2((x+10)^5)
Therefore, 5 log2(x+10) simplifies to log2((x+10)^5).
To solve the equation log4(3x+4) = 0, we first need to rewrite it in exponential form.
The logarithmic equation log4(3x+4) = 0 can be rewritten as 4^0 = 3x+4.
Since any number raised to the power of 0 is 1, we have 1 = 3x + 4.
Subtracting 4 from both sides gives us:
1 - 4 = 3x
-3 = 3x
Dividing by 3 on both sides:
x = -1
Therefore, the solution to the equation log4(3x+4) = 0 is x = -1.
Now, let's simplify the expression 5 log2(x+10).
Using the logarithmic property log_a(x^b) = blog_a(x), we can rewrite the expression as:
5 log2(x+10) = log2((x+10)^5)
Therefore, 5 log2(x+10) simplifies to log2((x+10)^5).