(x2-x+8)(x2-x-6)=120

Предыдущий
вопрос Следующий
вопрос

First, we will expand the left side of the equation:

(x^2 - x + 8)(x^2 - x - 6) = 120

x^4 - x^3 - 6x^2 - x^3 + x^2 + 6x + 8x^2 - 8x - 48 = 120

x^4 - 2x^3 + 15x^2 - 8x - 48 = 120

Now, we will rearrange the equation to set it equal to 0:

x^4 - 2x^3 + 15x^2 - 8x - 168 = 0

Since this is a quartic equation, it may be difficult to find the exact roots. You can use numerical methods or a graphing calculator to approximate the solutions.