(4х+1)(х+5)=(4х+1)(3х+2)

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First, let's expand both sides of the equation:

Left side:
(4x + 1)(x + 5)
= 4x^2 + 20x + x + 5
= 4x^2 + 21x + 5

Right side:
(4x + 1)(3x + 2)
= 12x^2 + 8x + 3x + 2
= 12x^2 + 11x + 2

Now, we can compare both sides of the equation:

4x^2 + 21x + 5 = 12x^2 + 11x + 2

Subtract 12x^2 and 11x from both sides:

-8x^2 + 10x + 5 = 2

Subtract 2 from both sides:

-8x^2 + 10x + 3 = 0

This is a quadratic equation, and we can solve it by factoring or using the quadratic formula. After factoring or using the quadratic formula, we can find the values of x that satisfy the equation.