Log35(1/5)+log35(1/7)

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To simplify this expression, we can use the property of logarithms that states log(base a)(b) + log(base a)(c) = log(base a)(b * c).

Therefore, log35(1/5) + log35(1/7) = log35((1/5) * (1/7)) = log35(1/35) = -1.

So, log35(1/5) + log35(1/7) simplifies to -1.