Sin32 cos 28 +cos32 sin 28

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вопрос

To find the value of the expression sin(32)cos(28) + cos(32)sin(28), we can use the trigonometric identity for the sine of the sum of two angles:

sin(a + b) = sin(a)cos(b) + cos(a)sin(b)

Therefore, sin(32)cos(28) + cos(32)sin(28) can be rewritten as sin(32 + 28):

sin(32)cos(28) + cos(32)sin(28) = sin(60)

Using the special right triangle where the angles are 30-60-90, sin(60) = √3 / 2

Therefore, the value of the expression sin(32)cos(28) + cos(32)sin(28) is √3 / 2.