Arctg1+ arccos(-1/2)+ arcsin(-1/2)

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вопрос

To find the values of arctan(1), arccos(-1/2), and arcsin(-1/2) we need to use a calculator or lookup table. Here are the values:

arctan(1) = π/4
arccos(-1/2) = 2π/3
arcsin(-1/2) = -π/6

Now we can add these values together:

π/4 + 2π/3 - π/6

To add these fractions, we need to find a common denominator, which in this case is 12:

(3π + 8π - 2π) / 12
= 9π / 12
= 3π / 4

Therefore, arctan(1) + arccos(-1/2) + arcsin(-1/2) is equal to 3π/4.