To solve this trigonometric equation, we can use the sum and difference formulas for sine and cosine.
Using the sum and difference formulas, we have:sin(3x) cos(2x) = sin(3x + 2x) = sin(5x)sin(2x) cos(3x) = sin(2x + 3x) = sin(5x)
Therefore, sin(3x) cos(2x) = sin(2x) cos(3x) when 5x = 0 + n2π or 5x = π + n2π, where n is an integer.
To solve this trigonometric equation, we can use the sum and difference formulas for sine and cosine.
Using the sum and difference formulas, we have:
sin(3x) cos(2x) = sin(3x + 2x) = sin(5x)
sin(2x) cos(3x) = sin(2x + 3x) = sin(5x)
Therefore, sin(3x) cos(2x) = sin(2x) cos(3x) when 5x = 0 + n2π or 5x = π + n2π, where n is an integer.