Log (база 7) 49= log (база 5) 125= log (база 3) 81= log (база 2) 32= lg 10000= lg ]10^7= lg 0.001= lg 0.00001=

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Let's solve each logarithm:

log₇ 49 = 2, because 7^2 = 49log₅ 125 = 3, because 5^3 = 125log₃ 81 = 4, because 3^4 = 81log₂ 32 = 5, because 2^5 = 32lg 10000 = 4, because 10^4 = 10000lg (10^7) = 7, because 10^7 = 10000000lg 0.001 = -3, because 10^-3 = 0.001lg 0.00001 = -5, because 10^-5 = 0.00001

So the values of the given logarithms are:
log₇ 49 = 2
log₅ 125 = 3
log₃ 81 = 4
log₂ 32 = 5
lg 10000 = 4
lg (10^7) = 7
lg 0.001 = -3
lg 0.00001 = -5