Given that A5 = -2 and A25 = -48, we can use the arithmetic progression formula to find a1 and d.
The formula for the nth term of an arithmetic progression is: An = a1 + (n-1)d
Substitute n = 5 into the formulaA5 = a1 + (5-1)-2 = a1 + 4d .............(1)
Substitute n = 25 into the formulaA25 = a1 + (25-1)-48 = a1 + 24d ...........(2)
We have a system of linear equations-2 = a1 + 4-48 = a1 + 24d
Subtract equation (1) from equation (2)-48 - (-2) = 24d - 4-46 = 20d = -46/2d = -2.3
Now substitute d = -2.3 into equation (1)-2 = a1 + 4(-2.3-2 = a1 - 9.a1 = -2 + 9.a1 = 7.2
Therefore, a1 = 7.2 and d = -2.3.
Given that A5 = -2 and A25 = -48, we can use the arithmetic progression formula to find a1 and d.
The formula for the nth term of an arithmetic progression is: An = a1 + (n-1)d
Substitute n = 5 into the formula
A5 = a1 + (5-1)
-2 = a1 + 4d .............(1)
Substitute n = 25 into the formula
A25 = a1 + (25-1)
-48 = a1 + 24d ...........(2)
We have a system of linear equations
-2 = a1 + 4
-48 = a1 + 24d
Subtract equation (1) from equation (2)
-48 - (-2) = 24d - 4
-46 = 20
d = -46/2
d = -2.3
Now substitute d = -2.3 into equation (1)
-2 = a1 + 4(-2.3
-2 = a1 - 9.
a1 = -2 + 9.
a1 = 7.2
Therefore, a1 = 7.2 and d = -2.3.