(y+ 1) * 18= 36 + 12 * (y+1)(k+ 5) * 7 - 54 = ( k+5) * 417*(c-2) - 36 = 19+ (c-2) * 12

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вопрос

Let's simplify the equations:

1) (y+1) * 18 = 36
18y + 18 = 36
18y = 18
y = 1

2) (y+1)(k+5) 7 = 54
(1+1)(k+5) 7 = 54
2(k+5) * 7 = 54
14k + 70 = 54
14k = -16
k = -16/14
k = -8/7

3) (k+5) 4 = 17
(-8/7 + 5) 17 = 54
(37/7) * 17 = 54
629/7 = 54
89.857 = 54

4) 19 + (c-2) * 12 = 36
19 + 12c - 24 = 36
12c - 5 = 36
12c = 41
c = 41/12

Therefore, the solutions for the equations are: