3*(1/sqrt(3))^(2-3x) = 1/9

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вопрос

To solve for x, we first need to simplify the equation:

3*(1/sqrt(3))^(2-3x) = 1/9

First, simplify 1/sqrt(3) to get rid of the division:

1/sqrt(3) = sqrt(3)/3

Now we can substitute this back into the equation:

3*(sqrt(3)/3)^(2-3x) = 1/9
(sqrt(3))^(2-3x) = 1/9

Next, simplify the left side of the equation:

(sqrt(3))^(2-3x) = (3)^(1-3x)

Now we can rewrite the equation as:

(3)^(1-3x) = 1/9

Now we can solve for x by equating the powers of 3 on both sides of the equation:

1-3x = -2

-3x = -3

x = 1

Therefore, the solution to the equation is x = 1.