S1=1+2+...+99 S2=3+6+9+...+99 s=?

Предыдущий
вопрос Следующий
вопрос

To find the sum of S1, we use the formula for the sum of an arithmetic series:

S1 = n/2 (first term + last term)
S1 = 99/2 (1 + 99)
S1 = 4950

To find the sum of S2, we first find the number of terms in the series:

99 = 3 + (n-1) * 3
99 = 3n
n = 33

Next, we use the formula for the sum of an arithmetic series again:

S2 = n/2 (first term + last term)
S2 = 33/2 (3 + 99)
S2 = 33/2 * 102
S2 = 1683

Therefore, s = S1 - S2 = 4950 - 1683 = 3267.