я) (\frac{1}{9}x^2 + \frac{2}{15}xy + \frac{1}{25}y^2) = (\frac{1}{3}x\cdot\frac{1}{3}x + 2\cdot\frac{1}{3}x\cdot\frac{1}{5}y + \frac{1}{5}y\cdot\frac{1}{5}y) = ((\frac{1}{3}x + \frac{1}{5}y)^2)
д) 100b^2 + 9c^2 - 60bc = (10b)^2 + 2 \cdot 10b \cdot 3c + (3c)^2 = (10b - 3c)^2
е) 49x^2 + 12xy + 64y^2 = 7x^2 + 2 \cdot 7x \cdot 4y + 8^2 = (7x + 8y)^2
я) (\frac{1}{9}x^2 + \frac{2}{15}xy + \frac{1}{25}y^2) = (\frac{1}{3}x\cdot\frac{1}{3}x + 2\cdot\frac{1}{3}x\cdot\frac{1}{5}y + \frac{1}{5}y\cdot\frac{1}{5}y) = ((\frac{1}{3}x + \frac{1}{5}y)^2)
д) 100b^2 + 9c^2 - 60bc = (10b)^2 + 2 \cdot 10b \cdot 3c + (3c)^2 = (10b - 3c)^2
е) 49x^2 + 12xy + 64y^2 = 7x^2 + 2 \cdot 7x \cdot 4y + 8^2 = (7x + 8y)^2