Y1/2 sin(x-P/6) y=sinx/2-1

Предыдущий
вопрос Следующий
вопрос

To calculate the product of these two functions, we simply multiply them together:

(y1/2) sin(x-P/6) (sinx/2 - 1)

= (1/2) sin(x-P/6) sin(x/2) - sin(x-P/6)

= (1/2) (sin(x)cos(P/6) - cos(x)sin(P/6)) (sin(x)cos(1/2) + cos(x)sin(1/2)) - sin(x-P/6)

= (1/2) (sin(x)cos(P/6)sin(x)cos(1/2) + sin(x)cos(P/6)cos(x)sin(1/2) - cos(x)sin(P/6)sin(x)cos(1/2) - cos(x)sin(P/6)*cos(x)sin(1/2)) - sin(x-P/6)

= (1/2) * (sin(x)cos(P/6)cos(1/2)sin(x) + sin(x)cos(P/6)sin(1/2)cos(x) - cos(x)sin(P/6)cos(1/2)sin(x) - cos(x)sin(P/6)sin(1/2)cos(x)) - sin(x-P/6)

= (1/2) (0.5sin(2x) + cos(3x - P/6) + 0.5sin(P/6) - 1/2)

Therefore, the product of the two functions is given by 0.5*sin(2x) + cos(3x - P/6) + 0.5sin(P/6) - 1/2.