Q1=9 нкл q2=-1 нкл l=50см q3=3нКл

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вопрос

To find the direction of the force experienced by q3 due to the other two charges (q1 and q2), we can use the principle of superposition, which states that the total force on a charge is the vector sum of the forces due to each individual charge.

The force experienced by q3 due to q1 can be calculated using Coulomb's law:

F1 = k |q1q3| / r^2

Where k is Coulomb's constant (k ≈ 9 x 10^9 Nm^2/C^2), q1 and q3 are the magnitudes of the charges, and r is the distance between the charges. Plugging in the values:

F1 = (9 x 10^9) |9 x 10^-9 3 x 10^-9| / (0.5)^2
F1 = 121.5 x 10^-18 / 0.25
F1 = 486 x 10^-18
F1 = 4.86 x 10^-16 N

The force experienced by q3 due to q1 is 4.86 x 10^-16 N in the direction from q1 to q3.

The force experienced by q3 due to q2 can be calculated in the same way:

F2 = k |q2q3| / r^2

Plugging in the values:

F2 = (9 x 10^9) * |-1 x 3 x 10^-9| / (0.5)^2
F2 = 27 x 10^-9 / 0.25
F2 = 108 x 10^-9
F2 = 1.08 x 10^-7 N

The force experienced by q3 due to q2 is 1.08 x 10^-7 N in the direction from q2 to q3.

Therefore, the net force on q3 due to q1 and q2 is the vector sum of F1 and F2. Since they are in opposite directions, the net force will depend on their magnitudes and direction of each other.