Q=6*10 в-2Кл , С=6*10в-2Ф Е-?

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вопрос

To calculate the energy stored in the capacitor, we can use the formula:

E = 1/2 C V^2

Given that Q = 610^-2 Кл and C = 610^-2 Ф, we first need to calculate the voltage (V) across the capacitor.

Q = C V
610^-2 Кл = 610^-2 Ф V
V = 1

Now we can calculate the energy (E):

E = 1/2 C V^2
E = 1/2 610^-2 Ф (1)^2
E = 1/2 610^-2
E = 310^-2

Therefore, the energy stored in the capacitor is 3*10^-2 J.