N1=3×10^16 n2=8.5×10^18 M1=201×10^-3 M2=71×10^-3R1(ро),R2=?

Предыдущий
вопрос Следующий
вопрос

To find the value of R2, we can use the formula for calculating the resistance of a material:

R = ρ * L / A

Where:

Since we are given the resistivities, lengths, and cross-sectional areas of two materials (R1, ρ1, M1 and R2, ρ2, M2), we can set up two equations and solve for R2.

For material 1:
R1 = ρ1 L1 / A1
R1 = 201×10^-3 3×10^16 / A1

For material 2:
R2 = ρ2 L2 / A2
R2 = ρ2 8.5×10^18 / A2

Now we need to find the cross-sectional area (A2) of material 2. We can calculate the cross-sectional area using the mass (M2) of the material and the length (L2) of the material.

A2 = M2 / (ρ2 * L2)
A2 = 71×10^-3 / (8.5×10^18)

Now we can substitute the values of A2 and ρ2 into the equation for R2:

R2 = 71×10^-3 / (8.5×10^18) * (8.5×10^18) / A2
R2 = 71×10^-3

Therefore, R2 = 71×10^-3.