Q1=25 нКл q2=24нКл d1=10см d2=20см найти E

Предыдущий
вопрос Следующий
вопрос

To find the electric field (E) between the two charges, we can use the formula for electric field due to a point charge:

E = k |q1| / r^2 + k |q2| / r^2

Where:
E = electric field
k = Coulomb's constant = 8.9875 x 10^9 N m^2/C^2
q1 = magnitude of charge 1 = 25 nC = 25 x 10^-9 C
q2 = magnitude of charge 2 = 24 nC = 24 x 10^-9 C
d1 = distance to charge 1 = 10 cm = 0.1 m
d2 = distance to charge 2 = 20 cm = 0.2 m

Plugging in the values:

E = (8.9875 x 10^9 N m^2/C^2) (25 x 10^-9 C) / (0.1^2) + (8.9875 x 10^9 N m^2/C^2) (24 x 10^-9 C) / (0.2^2)

E = (2.2469 x 10^1 N/C) + (4.4939 x 10^1 N/C)

E = 6.7408 x 10^1 N/C

Therefore, the electric field between the two charges is 67.408 N/C.