To find the lengths of BC and AC, we will use the sine and cosine trigonometric ratios.
GivenAngle C = 90Angle A = 60Side AB = 5√3
First, let's find the length of side BC (opposite angle A):
sin(60°) = BC / Asin(60°) = BC / 5√BC = 5√3 sin(60°BC ≈ 5 0.86BC ≈ 4.33
Next, let's find the length of side AC (opposite right angle C):
cos(60°) = AC / Acos(60°) = AC / 5√AC = 5√3 cos(60°AC ≈ 5 0.AC ≈ 2.50
Therefore, the length of side BC is approximately 4.33 and the length of side AC is approximately 2.50.
To find the lengths of BC and AC, we will use the sine and cosine trigonometric ratios.
Given
Angle C = 90
Angle A = 60
Side AB = 5√3
First, let's find the length of side BC (opposite angle A):
sin(60°) = BC / A
sin(60°) = BC / 5√
BC = 5√3 sin(60°
BC ≈ 5 0.86
BC ≈ 4.33
Next, let's find the length of side AC (opposite right angle C):
cos(60°) = AC / A
cos(60°) = AC / 5√
AC = 5√3 cos(60°
AC ≈ 5 0.
AC ≈ 2.50
Therefore, the length of side BC is approximately 4.33 and the length of side AC is approximately 2.50.