Ac=7см;BC=9см;C=80% AB-?A-?A-?

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вопрос Следующий
вопрос

To find the length of AB and the measure of angles A and B, we can start by using the law of cosines.

Let's denote the length of AB as x. Then, using the law of cosines:

x^2 = 7^2 + 9^2 - 2(7)(9)cos(80°)
x^2 = 49 + 81 - 126cos(80°)
x^2 = 130 - 126cos(80°)

Now, we can calculate the value of x:

x = √(130 - 126cos(80°))

x ≈ √(130 - 126cos(80°)) ≈ 7.13 cm

Next, we can find the angles A and B using the law of sines:

sin(A) / 7 = sin(80°) / 7.13
sin(B) / 9 = sin(80°) / 7.13

Solving for A and B:

A = arcsin(7sin(80°) / 7.13) ≈ 23.91°

B = arcsin(9sin(80°) / 7.13) ≈ 56.09°

Therefore, AB is approximately 7.13 cm, angle A is approximately 23.91°, and angle B is approximately 56.09°.