Given that EA:AF=2:5, we can write AF as 5x and EA as 2x, where x is a positive constant.
Since m=KA and n=KF, we know that m+n=AF=5x. Therefore, KA + KF = 5x.
We also know that KF = KE, so KE + KA = 5x. Since KA = m, we can substitute KA with m to get KE + m = 5x.
Therefore, KE = 5x - m.
Given that EA:AF=2:5, we can write AF as 5x and EA as 2x, where x is a positive constant.
Since m=KA and n=KF, we know that m+n=AF=5x. Therefore, KA + KF = 5x.
We also know that KF = KE, so KE + KA = 5x. Since KA = m, we can substitute KA with m to get KE + m = 5x.
Therefore, KE = 5x - m.