To find the cosine of the negative angle, you can use the following trigonometric identity:
cos(-θ) = cos(θ)
Therefore, cos(-SinA) = cos(SinA)
Since SinA = √3/2, we can use the Pythagorean theorem to calculate the cosine. CosA = ±√(1 - Sin^2(A)). So, in this case:
cos(A) = ±√(1 - (√3/2)^2)cos(A) = ±√(1 - 3/4)cos(A) = ±√(1/4)cos(A) = ±1/2
Therefore, the cosine of -SinA is the same as the cosine of SinA, which is ±1/2.
To find the cosine of the negative angle, you can use the following trigonometric identity:
cos(-θ) = cos(θ)
Therefore, cos(-SinA) = cos(SinA)
Since SinA = √3/2, we can use the Pythagorean theorem to calculate the cosine. CosA = ±√(1 - Sin^2(A)). So, in this case:
cos(A) = ±√(1 - (√3/2)^2)
cos(A) = ±√(1 - 3/4)
cos(A) = ±√(1/4)
cos(A) = ±1/2
Therefore, the cosine of -SinA is the same as the cosine of SinA, which is ±1/2.