Since DE = CE, triangle DEC is an isosceles triangle.

Since ∢CED = 128°, then ∢CDE = 128° as well.

Therefore, the sum of angles in triangle DEC is:

∢DCE + ∢CDE + ∢CED = 180°
∢DCE + 128° + 128° = 180°
∢DCE = 180° - 256°
∢DCE = -76°

Since DE = CE, then triangle CED is also an isosceles triangle.

Therefore, ∢DEC = ∢DCE = -76°

Now, in triangle FCE,

∢FCE + ∢CE + ∢CEF = 180°
∢FCE + 128° + 128° = 180°
∢FCE = 180° - 256°
∢FCE = -76°

So, the angle FCE is -76°.