Since DE = CE, triangle DEC is an isosceles triangle.
Since ∢CED = 128°, then ∢CDE = 128° as well.
Therefore, the sum of angles in triangle DEC is:
∢DCE + ∢CDE + ∢CED = 180°∢DCE + 128° + 128° = 180°∢DCE = 180° - 256°∢DCE = -76°
Since DE = CE, then triangle CED is also an isosceles triangle.
Therefore, ∢DEC = ∢DCE = -76°
Now, in triangle FCE,
∢FCE + ∢CE + ∢CEF = 180°∢FCE + 128° + 128° = 180°∢FCE = 180° - 256°∢FCE = -76°
So, the angle FCE is -76°.
Since DE = CE, triangle DEC is an isosceles triangle.
Since ∢CED = 128°, then ∢CDE = 128° as well.
Therefore, the sum of angles in triangle DEC is:
∢DCE + ∢CDE + ∢CED = 180°
∢DCE + 128° + 128° = 180°
∢DCE = 180° - 256°
∢DCE = -76°
Since DE = CE, then triangle CED is also an isosceles triangle.
Therefore, ∢DEC = ∢DCE = -76°
Now, in triangle FCE,
∢FCE + ∢CE + ∢CEF = 180°
∢FCE + 128° + 128° = 180°
∢FCE = 180° - 256°
∢FCE = -76°
So, the angle FCE is -76°.