cos A = 1/sqrt(1 + tg^2 B) = 1/sqrt(1 + tg^2(B))cos A = 1/sqrt(1 + (tg B)^2) = 1/sqrt(1 + (tg B)^2)cos A = 1/sqrt(1 + (tg B)^2) = 1/sqrt(1 + (tg 45)^2)cos A = 1/sqrt(1 + (tg 45)^2) = 1/sqrt(1 + 1)cos A = 1/sqrt(2) = sqrt(2)/2
Ответ: cos A = sqrt(2)/2
cos A = 1/sqrt(1 + tg^2 B) = 1/sqrt(1 + tg^2(B))
cos A = 1/sqrt(1 + (tg B)^2) = 1/sqrt(1 + (tg B)^2)
cos A = 1/sqrt(1 + (tg B)^2) = 1/sqrt(1 + (tg 45)^2)
cos A = 1/sqrt(1 + (tg 45)^2) = 1/sqrt(1 + 1)
cos A = 1/sqrt(2) = sqrt(2)/2
Ответ: cos A = sqrt(2)/2