To find AC and BC, we first need to find the length of the line segment AB.
Given that AB = 5√2, we can apply the Pythagorean theorem to find the lengths of AC and BC.
Let AC = x and BC = y.
Using the Pythagorean theorem on right triangle ABC: AC^2 + BC^2 = AB^2 x^2 + y^2 = (5√2)^2 x^2 + y^2 = 50
We can't solve for x and y individually with just this equation. However, we do know that AC and BC are perpendicular to each other, so they divide AB into two segments in a ratio.
Since AB was divided solely using 45-45-90 triangle, the ratio it is divided in is the 1:1 ratio.
To find AC and BC, we first need to find the length of the line segment AB.
Given that AB = 5√2, we can apply the Pythagorean theorem to find the lengths of AC and BC.
Let AC = x and BC = y.
Using the Pythagorean theorem on right triangle ABC:
AC^2 + BC^2 = AB^2
x^2 + y^2 = (5√2)^2
x^2 + y^2 = 50
We can't solve for x and y individually with just this equation. However, we do know that AC and BC are perpendicular to each other, so they divide AB into two segments in a ratio.
Since AB was divided solely using 45-45-90 triangle, the ratio it is divided in is the 1:1 ratio.
So, AC = BC = √25 = 5.
Therefore, AC = BC = 5.