First, we need to find the length of AB using the tangent formula:
tan(A) = BC / AB0.25 = 4 / ABAB = 4 / 0.25AB = 16
Next, we use Pythagoras' theorem to find the length of AC:
AC^2 = AB^2 + BC^2AC^2 = 16^2 + 4^2AC^2 = 256 + 16AC^2 = 272AC = √272AC ≈ 16.49
Therefore, the length of AC is approximately 16.49.
First, we need to find the length of AB using the tangent formula:
tan(A) = BC / AB
0.25 = 4 / AB
AB = 4 / 0.25
AB = 16
Next, we use Pythagoras' theorem to find the length of AC:
AC^2 = AB^2 + BC^2
AC^2 = 16^2 + 4^2
AC^2 = 256 + 16
AC^2 = 272
AC = √272
AC ≈ 16.49
Therefore, the length of AC is approximately 16.49.