аFe(OH)3 → Fe2O3 + 3H2Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2HCl + Cr2O3 → CrCl3 + H24Al + 3O2 → 2Al2O3
b2Na + 2H2O → 2NaOH + HAlCl3 + 3NaOH → Al(OH)3 + 3NaC2Al + 3I2 → 2AlIFe2O3 + 6HNO3 → 2Fe(NO3)3 + 3H2O
Рассчитаем относительные молекулярные массы соединений и восстановим коэффициенты:
аFe(OH)3: 55.85 + (1.01 + 16.00) 3 = 106.92 g/moFe2O3: 55.85 2 + 16.00 3 = 159.70 g/moH2O: 2 1.01 + 16.00 = 18.02 g/mol
Fe(OH)3 → Fe2O3 + 3H2O
Al2O3: 26.98 2 + 16.00 3 = 101.96 g/moAl2(SO4)3: 26.98 2 + (32.07 + 16.00 4) * 3 = 342.15 g/mol
Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2O
HCl: 1.01 + 35.45 = 36.46 g/moCrCl3: 51.99 + 3 * 35.45 = 158.92 g/mol
2HCl + Cr2O3 → 2CrCl3 + 3H2O
Al: 26.98 g/moO2: 16.00 2 = 32.00 g/moAl2O3: 26.98 2 + 16.00 * 3 = 101.96 g/mol
4Al + 3O2 → 2Al2O3
bNa: 22.99 g/moNaOH: 22.99 + 16.00 + 1.01 = 40.00 g/moH2: 2 * 1.01 = 2.02 g/mol
2Na + 2H2O → 2NaOH + H2
AlCl3: 26.98 + 3 * 35.45 = 133.33 g/moNaCl: 22.99 + 35.45 = 58.44 g/mol
AlCl3 + 3NaOH → Al(OH)3 + 3NaCl
Al: 26.98 g/moI2: 2 126.90 = 253.80 g/moAlI3: 26.98 + 3 126.90 = 407.68 g/mol
2Al + 3I2 → 2AlI3
Fe2O3: 55.85 2 + 16.00 3 = 159.70 g/moHNO3: 1.01 + 14.01 + 3 16.00 = 63.01 g/moFe(NO3)3: 55.85 + 3 (14.01 + 3 * 16.00) = 241.95 g/mol
Fe2O3 + 6HNO3 → 2Fe(NO3)3 + 3H2O
а
Fe(OH)3 → Fe2O3 + 3H2
Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2
HCl + Cr2O3 → CrCl3 + H2
4Al + 3O2 → 2Al2O3
b
2Na + 2H2O → 2NaOH + H
AlCl3 + 3NaOH → Al(OH)3 + 3NaC
2Al + 3I2 → 2AlI
Fe2O3 + 6HNO3 → 2Fe(NO3)3 + 3H2O
Рассчитаем относительные молекулярные массы соединений и восстановим коэффициенты:
а
Fe(OH)3: 55.85 + (1.01 + 16.00) 3 = 106.92 g/mo
Fe2O3: 55.85 2 + 16.00 3 = 159.70 g/mo
H2O: 2 1.01 + 16.00 = 18.02 g/mol
Fe(OH)3 → Fe2O3 + 3H2O
Al2O3: 26.98 2 + 16.00 3 = 101.96 g/mo
Al2(SO4)3: 26.98 2 + (32.07 + 16.00 4) * 3 = 342.15 g/mol
Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2O
HCl: 1.01 + 35.45 = 36.46 g/mo
CrCl3: 51.99 + 3 * 35.45 = 158.92 g/mol
2HCl + Cr2O3 → 2CrCl3 + 3H2O
Al: 26.98 g/mo
O2: 16.00 2 = 32.00 g/mo
Al2O3: 26.98 2 + 16.00 * 3 = 101.96 g/mol
4Al + 3O2 → 2Al2O3
b
Na: 22.99 g/mo
NaOH: 22.99 + 16.00 + 1.01 = 40.00 g/mo
H2: 2 * 1.01 = 2.02 g/mol
2Na + 2H2O → 2NaOH + H2
AlCl3: 26.98 + 3 * 35.45 = 133.33 g/mo
NaCl: 22.99 + 35.45 = 58.44 g/mol
AlCl3 + 3NaOH → Al(OH)3 + 3NaCl
Al: 26.98 g/mo
I2: 2 126.90 = 253.80 g/mo
AlI3: 26.98 + 3 126.90 = 407.68 g/mol
2Al + 3I2 → 2AlI3
Fe2O3: 55.85 2 + 16.00 3 = 159.70 g/mo
HNO3: 1.01 + 14.01 + 3 16.00 = 63.01 g/mo
Fe(NO3)3: 55.85 + 3 (14.01 + 3 * 16.00) = 241.95 g/mol
Fe2O3 + 6HNO3 → 2Fe(NO3)3 + 3H2O