B2H6 + O2 -> B2O3 + H2O
The balanced chemical equation for the combustion of diborane (B2H6) to form two oxides is:
2B2H6 + 3O2 -> 2B2O3 + 3H2O
Therefore, when diborane burns in the presence of oxygen, it forms diboron trioxide (B2O3) and water (H2O).
B2H6 + O2 -> B2O3 + H2O
The balanced chemical equation for the combustion of diborane (B2H6) to form two oxides is:
2B2H6 + 3O2 -> 2B2O3 + 3H2O
Therefore, when diborane burns in the presence of oxygen, it forms diboron trioxide (B2O3) and water (H2O).